{VERSION 6 0 "IBM INTEL NT" "6.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Comment" 2 18 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 257 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 258 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 259 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 260 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 } {CSTYLE "" -1 261 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 262 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Text Output" -1 6 1 {CSTYLE "" -1 -1 "Cour ier" 1 10 0 0 255 1 2 2 2 2 2 1 2 1 3 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 } {PSTYLE "Maple Output" -1 11 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Outpu t" -1 12 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 } 1 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Plot" -1 13 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Normal" -1 256 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 1 0 0 0 0 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 0 "" 0 "" {TEXT -1 79 "Para come\347ar, vamos jus tificar algo que fizemos ao resolver a equa\347\343o log\355stica" }} {PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 256 "" 0 "" {XPPEDIT 18 0 "diff( y(t),t)=y(t)*(1-y(t))" "6#/-%%diffG6$-%\"yG6#%\"tGF**&-F(6#F*\"\"\",&F .F.-F(6#F*!\"\"F." }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 101 "Qua ndo resolvemos a equa\347\343o acima, simplesmente jogamos fora os m \363dulos que apareciam ao integrarmos " }{XPPEDIT 18 0 "1/u" "6#*&\" \"\"F$%\"uG!\"\"" }{TEXT -1 3 " e " }{XPPEDIT 18 0 "1/(1-u)" "6#*&\"\" \"F$,&F$F$%\"uG!\"\"F'" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 33 "A solu\347\343o que encontr\341vamos era (" }{TEXT 256 3 "com" } {TEXT -1 22 " as barras de m\363dulo):" }}{PARA 0 "" 0 "" {TEXT -1 0 " " }}{PARA 256 "" 0 "" {XPPEDIT 18 0 "abs(y(t)/(1-y(t)))=e^(c0)*e^t" "6 #/-%$absG6#*&-%\"yG6#%\"tG\"\"\",&F,F,-F)6#F+!\"\"F0*&)%\"eG%#c0GF,)F3 F+F," }{TEXT -1 1 "," }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 " " {TEXT -1 107 "que a princ\355pio t\355nhamos que analisar perto de y =1 e y=0 (onde a express\343o dentro do m\363dulo muda de sinal)." }} {PARA 0 "" 0 "" {TEXT -1 9 "Usando o " }{TEXT 257 33 "teorema de exist \352ncia e unicidade" }{TEXT -1 74 ", vemos entretanto que a express \343o nunca muda de sinal. Se para algum t0, " }{XPPEDIT 18 0 "y(t0)/( 1-y(t0))" "6#*&-%\"yG6#%#t0G\"\"\",&F(F(-F%6#F'!\"\"F," }{TEXT -1 68 " \351 positivo, para todo t ser\341 positivo (idem para negativo ou ze ro)." }}{PARA 0 "" 0 "" {TEXT -1 52 "Isso permite que simplesmente tro quemos a constante " }{TEXT 258 8 "positiva" }{TEXT -1 1 " " } {XPPEDIT 18 0 "e^(c0)" "6#)%\"eG%#c0G" }{TEXT -1 40 " por uma constant e com sinal irrestrito " }{XPPEDIT 18 0 "K0" "6#%#K0G" }{TEXT -1 1 ". " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 48 "# conferindo...\nedo:=diff(y(t),t)= y(t)*(1-y(t));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$edoG/-%%diffG6$-% \"yG6#%\"tGF,*&F)\"\"\",&F.F.F)!\"\"F." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 22 "dsolve(\{edo,y(0)=y0\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%\"yG6#%\"tG,$*&%#y0G\"\"\",(F*!\"\"-%$expG6#,$F'F-F- *&F.F+F*F+F+F-F-" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 84 "Note que a so lu\347\343o n\343o est\341 definida se o denominador se anular, o que \+ ocorre para t" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 34 "solve(-y0- exp(-t)+exp(-t)*y0=0,t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$-%#lnG6# *&%#y0G\"\"\",&F)!\"\"F(F)F+F+" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 208 "Note que somente no trecho 01 quanto para y0<0 teremos solu\347 \365es ilimitadas perto de " }{XPPEDIT 18 0 "-ln(y0/(-1+y0));" "6#,$-% #lnG6#*&%#y0G\"\"\",&F)!\"\"F(F)F+F+" }{TEXT -1 62 ", o que veremos ma is adiante, ao esbo\347ar gr\341ficos de solu\347\365es." }}{PARA 0 " " 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 65 "Vamos come\347ar c om o desenho de uma solu\347\343o que fica acima de y=1." }}{PARA 0 " " 0 "" {TEXT -1 39 "Para isso, vamos usar um comando novo, " }{TEXT 260 7 "DEplot," }{TEXT -1 20 " que fica no pacote " }{TEXT 259 7 "DETo ols" }{TEXT -1 2 ". " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 50 "wit h(DETools); # pacote com alguns comandos de edo" }}{PARA 12 "" 1 "" {XPPMATH 20 "6#7[s%+AreSimilarG%)DEnormalG%'DEplotG%)DEplot3dG%/DEplot _polygonG%(DFactorG%,DFactorLCLMG%,DFactorsolsG%+DchangevarG%6Function DecompositionG%%GCRDG%'GosperG%)HeunsolsG%.HomomorphismsG%3IsHyperexpo nentialG%%LCLMG%,MeijerGsolsG% " 0 "" {MPLTEXT 1 0 22 "dsolve(\{ed o,y(0)=y0\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%\"yG6#%\"tG,$*&%#y 0G\"\"\",(F*!\"\"-%$expG6#,$F'F-F-*&F.F+F*F+F+F-F-" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 186 "# solu\347\343o ilimitada perto de ln((y0- 1)/y0)\ny0:=1.1;\ncondi := [y(0)=y0];\ngsolup:=DEplot( edo, y(t), t=-3 ..5, condi,arrows=none,linecolor=black,view=[-5..5,-5..5],thickness=1, axes=normal):" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#y0G$\"#6!\"\"" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%&condiG7#/-%\"yG6#\"\"!$\"#6!\"\"" } }{PARA 6 "" 1 "" {TEXT -1 69 "Warning, plot may be incomplete, the fol lowing errors(s) were issued:" }}{PARA 6 "" 1 "" {TEXT -1 82 " canno t evaluate the solution further left of -2.3978982, probably a singula rity" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 33 "with(plots): # quer o usar display" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 1 " " }}{PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 85 "tblowup:=ln((y0-1)/y0);\ngreta:=implicitplot(t =tblowup,t=-5..5,y=-5..5,linestyle=dot):" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%(tblowupG$!+t_*yR#!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 41 "display(greta,gsolup,view=[-5..5,-5..5]);" }}{PARA 13 "" 1 "" {GLPLOT2D 344 332 332 {PLOTDATA 2 "6'-%'CURVESG6%X0%)anythingG6\"6#/%. source_rtableGX0F'F(6\"[gl'!%\"!!#iq\"X\"#!!!!404980000000000000000000 00000000C0032EE3B78624D9C014000000000000C0032EE3B78624D9C013355AF109BA 60C0032EE3B78624D9C012666666666666C0032EE3B78624D9C0119BC1577020C7C003 2EE3B78624D9C010CCCCCCCCCCCDC0032EE3B78624D9C0100227BDD6872DC0032EE3B7 8624D9C00E666666666666C0032EE3B78624D9C00CD11C4879DB27C0032EE3B78624D9 C00B333333333333C0032EE3B78624D9C0099DE91546A7F4C0032EE3B78624D9C00800 0000000000C0032EE3B78624D9C0066AB5E21374C1C0032EE3B78624D9C004CCCCCCCC CCCDC0032EE3B78624D9C0033782AEE0418EC0032EE3B78624D9C00199999999999AC0 032EE3B78624D9C000044F7BAD0E5BC0032EE3B78624D9BFFCCCCCCCCCCCCDC0032EE3 B78624D9BFF9A23890F3B64EC0032EE3B78624D9BFF6666666666666C0032EE3B78624 D9BFF33BD22A8D4FE8C0032EE3B78624D9BFF0000000000000C0032EE3B78624D9BFE9 AAD7884DD304C0032EE3B78624D9BFE3333333333333C0032EE3B78624D9BFD9BC1577 020C6EC0032EE3B78624D9BFC999999999999AC0032EE3B78624D9BF613DEEB4396A00 C0032EE3B78624D93FC999999999999AC0032EE3B78624D93FD9771DBC3126C6C0032E E3B78624D93FE3333333333333C0032EE3B78624D93FE9885BAAE56030C0032EE3B786 24D93FF0000000000000C0032EE3B78624D93FF32A943BD9167EC0032EE3B78624D93F F6666666666666C0032EE3B78624D93FF990FAA23F7CE4C0032EE3B78624D93FFCCCCC CCCCCCCDC0032EE3B78624D93FFFF76108A5E34BC0032EE3B78624D940019999999999 9AC0032EE3B78624D940032EE3B78624D9C0032EE3B78624D94004CCCCCCCCCCCDC003 2EE3B78624D940066216EAB9580CC0032EE3B78624D94008000000000000C0032EE3B7 8624D94009954A1DEC8B40C0032EE3B78624D9400B333333333333C0032EE3B78624D9 400CC87D511FBE72C0032EE3B78624D9400E666666666666C0032EE3B78624D9400FFB B08452F1A6C0032EE3B78624D94010CCCCCCCCCCCDC0032EE3B78624D940119771DBC3 126CC0032EE3B78624D94012666666666666C0032EE3B78624D94013310B755CAC06C0 032EE3B78624D940140000000000000000000000000000000000000000000000000000 00000000000000000000000000000000000000000000000000000000[gl'!%\"!!#aq \"T\"#!!!!C0032EE3B78624D9C014000000000000C0032EE3B78624D9C013355AF109 BA60C0032EE3B78624D9C012666666666666C0032EE3B78624D9C0119BC1577020C7C0 032EE3B78624D9C010CCCCCCCCCCCDC0032EE3B78624D9C0100227BDD6872DC0032EE3 B78624D9C00E666666666666C0032EE3B78624D9C00CD11C4879DB27C0032EE3B78624 D9C00B333333333333C0032EE3B78624D9C0099DE91546A7F4C0032EE3B78624D9C008 000000000000C0032EE3B78624D9C0066AB5E21374C1C0032EE3B78624D9C004CCCCCC CCCCCDC0032EE3B78624D9C0033782AEE0418EC0032EE3B78624D9C00199999999999A C0032EE3B78624D9C000044F7BAD0E5BC0032EE3B78624D9BFFCCCCCCCCCCCCDC0032E E3B78624D9BFF9A23890F3B64EC0032EE3B78624D9BFF6666666666666C0032EE3B786 24D9BFF33BD22A8D4FE8C0032EE3B78624D9BFF0000000000000C0032EE3B78624D9BF E9AAD7884DD304C0032EE3B78624D9BFE3333333333333C0032EE3B78624D9BFD9BC15 77020C6EC0032EE3B78624D9BFC999999999999AC0032EE3B78624D9BF613DEEB4396A 00C0032EE3B78624D93FC999999999999AC0032EE3B78624D93FD9771DBC3126C6C003 2EE3B78624D93FE3333333333333C0032EE3B78624D93FE9885BAAE56030C0032EE3B7 8624D93FF0000000000000C0032EE3B78624D93FF32A943BD9167EC0032EE3B78624D9 3FF6666666666666C0032EE3B78624D93FF990FAA23F7CE4C0032EE3B78624D93FFCCC CCCCCCCCCDC0032EE3B78624D93FFFF76108A5E34BC0032EE3B78624D9400199999999 999AC0032EE3B78624D940032EE3B78624D9C0032EE3B78624D94004CCCCCCCCCCCDC0 032EE3B78624D940066216EAB9580CC0032EE3B78624D94008000000000000C0032EE3 B78624D94009954A1DEC8B40C0032EE3B78624D9400B333333333333C0032EE3B78624 D9400CC87D511FBE72C0032EE3B78624D9400E666666666666C0032EE3B78624D9400F FBB08452F1A6C0032EE3B78624D94010CCCCCCCCCCCDC0032EE3B78624D940119771DB C3126CC0032EE3B78624D94012666666666666C0032EE3B78624D94013310B755CAC06 C0032EE3B78624D94014000000000000-%'COLOURG6&%$RGBG$\"\"\"\"\"!$F4F4F5- %*LINESTYLEG6#\"\"#-F$6&7S7$$!\"$F4%*undefinedG7$$!+OLLLG!\"*F@7$$!+pm mmEFDF@7$$!+-+++DFDF@7$$!+NLLLBFD$\"3w?'QwVo$*f\"!#;7$$!+ommm@FD$\"3qu +Nt3#R%[!#<7$$!+,+++?FD$\"3kmGappFYIFV7$$!+MLLL=FD$\"3,&)=i!Gx!=BFV7$$ !+nmmm;FD$\"3'))fG$y^&z#>FV7$$!+++++:FD$\"3y**)R1h^vo\"FV7$$!+LLLL8FD$ \"3&*[.98XVE:FV7$$!+mmmm6FD$\"3[X]L$\\'H79FV7$$!+#*********!#5$\"3I*[: m(eAG8FV7$$!+DLLL$)Fbp$\"3/tE(H!*3XE\"FV7$$!+emmmmFbp$\"3(en#G$\\l^@\" FV7$$!+\"*******\\Fbp$\"3AX*Hln4j<\"FV7$$!+CLLLLFbp$\"3CHpSn(4`9\"FV7$ $!+dmmm;Fbp$\"3fY^3p$=.7\"FV7$$F3FD$\"3')****))*******4\"FV7$$\"+xmmm; Fbp$\"3oTZ?@\"oL3\"FV7$$\"+WLLLLFbp$\"3Eq7yQznp5FV7$$\"+6+++]Fbp$\"3Oe VncnNe5FV7$$\"+ymmmmFbp$\"3Ou8#QKf*[5FV7$$\"+XLLL$)Fbp$\"3pGX6mR8T5FV7 $$\"+,+++5FD$\"3*f5-dg+Y.\"FV7$$\"+ommm6FD$\"3o)Rc=-M\"H5FV7$$\"+NLLL8 FD$\"3csUr_:bC5FV7$$\"+-+++:FD$\"3jZ]5(Q/2-\"FV7$$\"+pmmm;FD$\"33X^hK. 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y(t), t=-3..5, condi,arrows=none,linecolor=red,view=[-5..5,-5.. 5],thickness=1,axes=normal):" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#y0G $!\"\"F&" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&condiG7#/-%\"yG6#\"\"!$ !\"\"F," }}{PARA 6 "" 1 "" {TEXT -1 69 "Warning, plot may be incomplet e, the following errors(s) were issued:" }}{PARA 6 "" 1 "" {TEXT -1 82 " cannot evaluate the solution further right of 2.3978958, probab ly a singularity" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 96 "tblowup :=ln((y0-1)/y0);\ngreta:=implicitplot(t=tblowup,t=-5..5,y=-5..5,color= blue,linestyle=dot):" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%(tblowupG$\" +t_*yR#!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 43 "display(gret a,gsoldown,view=[-5..5,-5..5]);" }}{PARA 13 "" 1 "" {GLPLOT2D 417 296 296 {PLOTDATA 2 "6'-%'CURVESG6%X0%)anythingG6\"6#/%.source_rtableGX0F' F(6\"[gl'!%\"!!#iq\"X\"#!!!!4049800000000000000000000000000040032EE3B7 8624D9C01400000000000040032EE3B78624D9C013310B755CAC0640032EE3B78624D9 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"6#/,&-%%diffG6$-%\"yG6#%\"xGF+\"\"\"*&-%\"aG6#F+F,-F)6#F+F,F,-% \"bG6#F+" }{TEXT -1 3 ", " }{XPPEDIT 18 0 "y(x0)=y0" "6#/-%\"yG6#%#x0 G%#y0G" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 82 "Na verdade, gostar\355amos de ter uma f\363rmula par a a solu\347\343o geral do problema acima." }}{PARA 0 "" 0 "" {TEXT -1 78 "A boa not\355cia \351 que o problema \351 t\343o f\341cil, que \+ at\351 o Maple sabe essa f\363rmula:" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 35 "edo:=diff(y(x),x)+a(x)*y( x) = b(x);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$edoG/,&-%%diffG6$-%\" yG6#%\"xGF-\"\"\"*&-%\"aGF,F.F*F.F.-%\"bGF," }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "dsolve(\{edo,y(x0)=y0\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%\"yG6#%\"xG*&,&-%$IntG6$*&-%\"bG6#%$_z1G\"\"\"-%$exp G6#-F+6$-%\"aGF0/F1;%#x0GF1F2/F1;F " 0 "" {MPLTEXT 1 0 32 "m:=.25;\ng:=9.8;\nv0:=0;\nk:=1/30.;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"mG$\"#D!\"#" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"gG$\"#)*!\"\"" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>% #v0G\"\"!" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"kG$\"+LLLLL!#6" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 32 "edo1:=m*diff(v(t),t)=m*g-k*v (t);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%edo1G/,$*&$\"#D!\"#\"\"\"-% %diffG6$-%\"vG6#%\"tGF2F+F+,&$\"%]C!\"$F+*&$\"+LLLLL!#6F+F/F+!\"\"" }} }{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "dsolve(\{edo1,v(0)=v0\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%\"vG6#%\"tG,&#\"-++++]C\"+LLLLL\" \"\"*&#\"-++++]CF+F,-%$expG6#,$*(\"+LLLLLF,\",++++]#!\"\"F'F,F7F,F7" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "sol1:=rhs(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%sol1G,&#\"-++++]C\"+LLLLL\"\"\"*&#\"-++++]CF (F)-%$expG6#,$*(\"+LLLLLF)\",++++]#!\"\"%\"tGF)F4F)F4" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "plot(sol1,t=0..100);" }}{PARA 13 " " 1 "" {GLPLOT2D 506 286 286 {PLOTDATA 2 "6%-%'CURVESG6$7Z7$$\"\"!F)F( 7$$\"3)pmm;a)G\\a!#=$\"3erO_7;\"4:&!#<7$$\"3SLLL3x&)*3\"F0$\"3.I&eQ7X3 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"Curve 1" }}}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 23 "limit(sol1,t=infinity);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6##\"-++++]C\"+LLLLL" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "evalf(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+ ,++]t!\")" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 144 "Vemos, tanto pela f \363rmula da solu\347\343o, como pelo gr\341fico, que a velocidade n \343o cresce indefinidamente, mas tem um limite assint\363tico, chamad o de " }{TEXT 262 19 "velocidade terminal" }{TEXT -1 25 ", que no caso \351 73.5 m/s." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 48 "Considere agora v0=-20 m/s (jogamos para cima). " }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 24 "dsolve(\{edo1,v(0)=-20\});" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%\"vG6#%\"tG,&#\"-++++]C\"+LLLLL\" \"\"*&#\"-gmmm;JF+F,-%$expG6#,$*(\"+LLLLLF,\",++++]#!\"\"F'F,F7F,F7" } }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 13 "sol2:=rhs(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%sol2G,&#\"-++++]C\"+LLLLL\"\"\"*&#\"-gmmm;JF (F)-%$expG6#,$*(\"+LLLLLF)\",++++]#!\"\"%\"tGF)F4F)F4" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "plot(sol2,t=0..10);" }}{PARA 13 "" 1 "" {GLPLOT2D 624 312 312 {PLOTDATA 2 "6%-%'CURVESG6$7S7$$\"\"!F)$!#? F)7$$\"3emmm;arz@!#=$!3_GQU3H1P)RtcFE7$$ \"3!****\\7LRDX\"FE$!3kR(e@+&GPNFE7$$\"3%om;zR'ok;FE$!3oj$\\x'yr)Q\"FE 7$$\"33++D1J:w=FE$\"3%)QZ!*z[@LpF/7$$\"3oLLL3En$4#FE$\"3#p1&HwwduFFE7$ $\"3#pmmT!RE&G#FE$\"3a0]'>*GTeXFE7$$\"3D+++D.&4]#FE$\"3ARFqX4\"G^'FE7$ $\"3;+++vB_%)FE7$$\"33+++v'Hi#HFE$\"3)=b')*=&)>F27 $$\"3S++vV&RY2aFE$\"3C9iE!=#R.GF27$$ \"3Znm;zXu9cFE$\"33Dc`^$Ht#HF27$$\"34+++]y))GeFE$\"3)Q\\!=O;#=0$F27$$ \"3H++]i_QQgFE$\"3kX'RgF@-<$F27$$\"3b++D\"y%3TiFE$\"3S<'\\5it;G$F27$$ \"3+++]P![hY'FE$\"3],:CNT%>S$F27$$\"3iKLL$Qx$omFE$\"3i'4\\.wwp]$F27$$ \"3Y+++v.I%)oFE$\"31<8_-*Qgh$F27$$\"3?mm\"zpe*zqFE$\"3G'4Tt+!>7PF27$$ \"3;,++D\\'QH(FE$\"3$>&[:pxZ9QF27$$\"3%HL$e9S8&\\(FE$\"3.'oc![[43RF27$ $\"3s++D1#=bq(FE$\"3WjmV6HI.SF27$$\"3\"HLL$3s?6zFE$\"3s(R'e\"eRQ4%F27$ $\"3a***\\7`Wl7)FE$\"3mOxvG***f=%F27$$\"3enmmm*RRL)FE$\"3'fc8F^%HsUF27 $$\"3%zmmTvJga)FE$\"3%fm:tb4\"eVF27$$\"3]MLe9tOc()FE$\"3/2S4,2&3W%F27$ $\"31,++]Qk\\*)FE$\"31u&y2Li[^%F27$$\"3![LL3dg6<*FE$\"3spwK(=vtf%F27$$ \"3%ymmmw(Gp$*FE$\"3!QXU)*4R\"pYF27$$\"3C++D\"oK0e*FE$\"3Ya&)= " 0 "" {MPLTEXT 1 0 58 "# tempo de altura m\341xima(v=0)\ntmax:=fsolve(sol2=0,t=0..2);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%%tmaxG$\"+E-20=!\"*" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 65 "# altura m\341xima relativa ao ponto de largada\nint( sol2,t=0..tmax);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$!+UQtK " 0 "" {MPLTEXT 1 0 45 "# velocidade terminal\nlimit (sol2,t=infinity);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6##\"-++++]C\"+LLL LL" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "evalf(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+,++]t!\")" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{MARK "41" 0 }{VIEWOPTS 1 1 0 3 2 1804 1 1 1 1 } {PAGENUMBERS 0 1 2 33 1 1 }