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[SPAM] [obm-l] RES: [obm-l] [obm-l] Questão de indução matemática



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Ol=E1 Marcelo Salhab,

=20

Muito grato.

=20

Sds

=20

Rubens Kamimura=20

Assistente T=E9cnico III - CREA/SP 5062246285

CESP - Companhia Energ=E9tica de S=E3o Paulo

OMPTD - Capacita=E7=E3o e Desenvolvimento

Caixa Postal, 58 - CEP 15385-000

Ilha Solteira/SP - Brasil

Tel. +55-18-3704-4240 ramal 136/137

Tel./Fax +55-18-3704-6800

www.cesp.com.br

email: rubens.kamimura@xxxxxxxxxxx=20

Mens In Corpore Tantun Molen Regit

UNYK : 132 XOU

P Antes de imprimir pense em sua responsabilidade e compromisso com o =
MEIO
AMBIENTE.

=20

=20

=20

De: owner-obm-l@xxxxxxxxxxxxxx [mailto:owner-obm-l@xxxxxxxxxxxxxx] Em =
nome
de Marcelo Salhab Brogliato
Enviada em: ter=E7a-feira, 4 de mar=E7o de 2008 14:29
Para: obm-l@xxxxxxxxxxxxxx
Assunto: Re: [obm-l] [obm-l] Quest=E3o de indu=E7=E3o matem=E1tica

=20

Ol=E1 Rubens,

Essas demonstra=E7=F5es seguem todas a mesma id=E9ia...
vou fazer apenas o 2.1
veja que para n=3D1 =E9 v=E1lido

vamos supor valido para K e vamos mostrar que vale para K+1.
isto =E9:
Hip=F3tese: 1^2 + 2^2 + ... + k^2 =3D [k(k+1)(2k+1)]/6
Tese: 1^2 + 2^2 + ... + k^2 + (k+1)^2 =3D (k+1)(k+2)(2k+3)/6

Demo:
Sabemos que: 1^2 + 2^2 + .. + k^2 =3D k(k+1)(2k+1)/6
somando (k+1)^2 em ambos os lados, temos:
1^2 + 2^2 + ... + k^2 + (k+1)^2 =3D k(k+1)(2k+1)/6 + (k+1)^2

vamos apenas fatorar o lado direito, e mostrar que ele =E9 igual a
(k+1)(k+2)(2k+3)/6 =3D (k+1)(2k^2 + 7k + 6)/6
k(k+1)(2k+1)/6 + (k+1)^2 =3D (k+1)[ k(2k+1)/6 + (k+1) ] =3D (k+1)[ 2k^2 =
+ k + 6k
+ 6 ]/6 =3D (k+1)(2k^2 + 7k + 6)/6

logo, est=E1 provado por indu=E7=E3o.

abra=E7os,
Salhab




2008/3/3 Rubens Kamimura <rubens.kamimura@xxxxxxxxxxx>:

Ol=E1 turma da LISTA!!!

Algu=E9m desta LISTA, se habilitariam em me elucidar tal quest=E3o?

1. Sabendo, por defini=E7=E3o, que: a^0=3D1 e a^1=3Da, como poderemos =
provar por
indu=E7=E3o matem=E1tica sobre n, que a^m.a^n =3D a^(m+n), para qualquer =
m,n
pertencente ao conjunto dos n=FAmeros naturais?

2. Como podemos provar por indu=E7=E3o matem=E1tica:
2.1. 1^2+ 2^2+...+n^2 =3D [n(n+1)(2n+1)]/6, (n maior igual 1);
2.2. 1^3+ 2^3+...+n^3 =3D (1+2+...+n)^2, (n maior igual 1);
2.3. 1.2+2.3+...+n(n+1) =3D [n(n+1)(n+2)]/3, (n maior igual 1);

Abra=E7os

leigo e ne=F3fito...


=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
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<p class=3DMsoNormal><span =
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color:#1F497D'>Ol=E1 Marcelo Salhab,<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'><o:p>&nbsp;</o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Muito grato.<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'><o:p>&nbsp;</o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Sds<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'><o:p>&nbsp;</o:p></span></p>

<p class=3DMsoNormal><b><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Rubens Kamimura <o:p></o:p></span></b></p>

<p class=3DMsoNormal><span =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Assistente T=E9cnico III - CREA/SP =
5062246285<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>CESP - Companhia Energ=E9tica de S=E3o =
Paulo<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>OMPTD - Capacita=E7=E3o e =
Desenvolvimento<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Caixa Postal, 58 - CEP 15385-000<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Ilha Solteira/SP - Brasil<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Tel. +55-18-3704-4240 ramal 136/137<o:p></o:p></span></p>

<p class=3DMsoNormal><span lang=3DEN-US =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Tel./Fax +55-18-3704-6800<o:p></o:p></span></p>

<p class=3DMsoNormal><span lang=3DEN-US =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'><a =
href=3D"http://www.cesp.com.br";>www.cesp.com.br</a><o:p></o:p></span></p>=


<p class=3DMsoNormal><span lang=3DEN-US =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>email: <a =
href=3D"mailto:rubens.kamimura@xxxxxxxxxxx";>rubens.kamimura@xxxxxxxxxxx</=
a>
<o:p></o:p></span></p>

<p class=3DMsoNormal><b><span lang=3DEN-US =
style=3D'font-size:8.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Mens In Corpore Tantun Molen =
Regit<o:p></o:p></span></b></p>

<p class=3DMsoNormal =
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line-height:10.5pt'><b><span =
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color:#003366'>UNYK : 132 XOU<o:p></o:p></span></b></p>

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color:#1F497D'> </span></b><b><span =
style=3D'font-size:7.5pt;font-family:"Verdana","sans-serif";
color:green'>Antes de imprimir pense em sua responsabilidade e =
compromisso com
o MEIO AMBIENTE.</span></b><span =
style=3D'font-family:"Calibri","sans-serif";
color:#1F497D'><o:p></o:p></span></p>

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b><span
style=3D'font-size:10.0pt;font-family:"Tahoma","sans-serif"'>
owner-obm-l@xxxxxxxxxxxxxx [mailto:owner-obm-l@xxxxxxxxxxxxxx] <b>Em =
nome de </b>Marcelo
Salhab Brogliato<br>
<b>Enviada em:</b> ter=E7a-feira, 4 de mar=E7o de 2008 14:29<br>
<b>Para:</b> obm-l@xxxxxxxxxxxxxx<br>
<b>Assunto:</b> Re: [obm-l] [obm-l] Quest=E3o de indu=E7=E3o =
matem=E1tica<o:p></o:p></span></p>

</div>

<p class=3DMsoNormal><o:p>&nbsp;</o:p></p>

<p class=3DMsoNormal style=3D'margin-bottom:12.0pt'>Ol=E1 Rubens,<br>
<br>
Essas demonstra=E7=F5es seguem todas a mesma id=E9ia...<br>
vou fazer apenas o 2.1<br>
veja que para n=3D1 =E9 v=E1lido<br>
<br>
vamos supor valido para K e vamos mostrar que vale para K+1.<br>
isto =E9:<br>
Hip=F3tese: 1^2 + 2^2 + ... + k^2 =3D [k(k+1)(2k+1)]/6<br>
Tese: 1^2 + 2^2 + ... + k^2 + (k+1)^2 =3D (k+1)(k+2)(2k+3)/6<br>
<br>
Demo:<br>
Sabemos que: 1^2 + 2^2 + .. + k^2 =3D k(k+1)(2k+1)/6<br>
somando (k+1)^2 em ambos os lados, temos:<br>
1^2 + 2^2 + ... + k^2 + (k+1)^2 =3D k(k+1)(2k+1)/6 + (k+1)^2<br>
<br>
vamos apenas fatorar o lado direito, e mostrar que ele =E9 igual a
(k+1)(k+2)(2k+3)/6 =3D (k+1)(2k^2 + 7k + 6)/6<br>
k(k+1)(2k+1)/6 + (k+1)^2 =3D (k+1)[ k(2k+1)/6 + (k+1) ] =3D (k+1)[ 2k^2 =
+ k + 6k +
6 ]/6 =3D (k+1)(2k^2 + 7k + 6)/6<br>
<br>
logo, est=E1 provado por indu=E7=E3o.<br>
<br>
abra=E7os,<br>
Salhab<br>
<br>
<br>
<o:p></o:p></p>

<div>

<p class=3DMsoNormal>2008/3/3 Rubens Kamimura &lt;<a
href=3D"mailto:rubens.kamimura@xxxxxxxxxxx";>rubens.kamimura@xxxxxxxxxxx</=
a>&gt;:<o:p></o:p></p>

<p class=3DMsoNormal>Ol=E1 turma da LISTA!!!<br>
<br>
Algu=E9m desta LISTA, se habilitariam em me elucidar tal quest=E3o?<br>
<br>
1. Sabendo, por defini=E7=E3o, que: a^0=3D1 e a^1=3Da, como poderemos =
provar por<br>
indu=E7=E3o matem=E1tica sobre n, que a^m.a^n =3D a^(m+n), para qualquer =
m,n<br>
pertencente ao conjunto dos n=FAmeros naturais?<br>
<br>
2. Como podemos provar por indu=E7=E3o matem=E1tica:<br>
2.1. 1^2+ 2^2+...+n^2 =3D [n(n+1)(2n+1)]/6, (n maior igual 1);<br>
2.2. 1^3+ 2^3+...+n^3 =3D (1+2+...+n)^2, (n maior igual 1);<br>
2.3. 1.2+2.3+...+n(n+1) =3D [n(n+1)(n+2)]/3, (n maior igual 1);<br>
<br>
Abra=E7os<br>
<br>
leigo e ne=F3fito...<br>
<br>
<br>
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D<br>=

Instru=E7=F5es para entrar na lista, sair da lista e usar a lista em<br>
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target=3D"_blank">http://www.mat.puc-rio.br/~obmlistas/obm-l.html</a><br>=

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