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Re: [obm-l] Série
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- Subject: Re: [obm-l] Série
- From: "Gabriel Haeser" <ghaeser@xxxxxxxxx>
- Date: Mon, 31 Mar 2008 14:50:27 -0300
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soma[1/(n)(n+k)]=soma[(1/k).(1/n-1/(n+k))]=1/k.(soma[1/n]-soma[1/(n+k)])=Hk/k
2008/3/31, Rodrigo Renji <rodrigo.uff.math@xxxxxxxxx>:
Mostrar que
somatório de n=1 até infinito de 1/(n)(n+k) =Hk/k
onde Hk é o k-ésimo número harmônico, k>=1, k natural
Hk= somatorio de p=1 até k de 1/p
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