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[SPAM] [obm-l] ângulo doido



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Esse problema quase me deixou louco...se alguém conseguir resolver,  agradeço antecipadamente...
 Seja um um triângulo ABC. No lado Ac, marca-se um ponto D tal que o segmento BD divide o ângulo B que é de 60 graus em <ABD=20 Graus e <ABC=40 Graus. No lado AC, marca-se um ponto F tal que o ângulo C que é de 80 graus fica dividido em <FCD=10 graus e <FCB=70 graus. Seja P o ponto de intersecção entre os segmentos BD e CF. Traçando-se o segmento AS, S pertencente ao lado BC e sabendo-se que AS contém P, determine x=<ASC.
    Ruy



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